The activation energy of a reaction is 58.3kJ/"mole". The ratio of the – InterviewSolution

1.	The activation energy of a reaction is 58.3kJ/"mole". The ratio of the rate constants at 305 K and 300 K is about (R=8.3Jk^(-1)mol^(-1)) ("Antilog" 0.1667=1.468)
Answer» `1.25` `1.75` `1.5` `2.0` ANSWER :C

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