The active mass of `64 g` of `HI` in a `2-L` flask would beA. (A) `22:3:7`B. (B) `0.5:3:7`C. (C) `1:3:1`D. (D) `1:3:0.5`

The active mass of `64 g` of `HI` in a `2-L` flask would beA. (A) `22:

1.	The active mass of `64 g` of `HI` in a `2-L` flask would beA. (A) `22:3:7`B. (B) `0.5:3:7`C. (C) `1:3:1`D. (D) `1:3:0.5`
Answer» Correct Answer - D Molar conc.`=(22)/(44)=(1)/(2)` Moles of `H_(2)=(3)/(2) rArr "Moles of" N_(2)=(7)/(28)=(1)/(4)` Ratio of active massess`=1//2:3//2:1//4 "or"1:3:0.5`.

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The active mass of `64 g` of `HI` in a `2-L` flask would beA. (A) `22:3:7`B. (B) `0.5:3:7`C. (C) `1:3:1`D. (D) `1:3:0.5`

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