

InterviewSolution
Saved Bookmarks
1. |
The active mass of `64 g` of `HI` in a `2-L` flask would beA. `2`B. `1`C. `5`D. `0.25` |
Answer» Correct Answer - D Active mass = Concentration `= "mol" L^(-1)` `[HI]=64/(128xx2)=0.25 M` |
|