InterviewSolution
Saved Bookmarks
| 1. |
The activity of a certain preparation decreases `2.5` times after `7.0` days. Find its half time. |
|
Answer» If the half-life is `T` days `(2)^(-7//T)=(1)/(2.5)` Hence `(7)/(T)= (In 2.5)/(In 2)` or `T=(7In 2)/(In 2.5)= 5.30 days` |
|