1.

The activity of a radioactive nuclide is 2 xx 10^(7) disintegrations per minute (dpm). After 23.03 minutes, its activity is reduced to 2 xx 10^(6) dpm. What is the average life (in min) of this nuclide

Answer»

1000
10
1
0.1

Solution :`t = (2.303)/(lamda) "log"(N_(0))/(N)`
or, `lamda = (2.303)/(t) "log" (N_(0))/(N) = (2.303)/(23.03) "log" (2XX 10^(7))/(2 xx 10^(6))`
or, `lamda = 0.1 "MIN^(-1)`
Now, average lige `= (1)/(lamda) = (1)/(0.1) = 10` min


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