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The activity of a radioactive substance is 4700 per minute. Five minute later the activity is 2700 per minute. Find (a) decay constant and (b) half-life of the radioactive substance. |
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Answer» Solution :GIVEN : intial activity `A_(0)=lambda N_(0)=4700` finalactivityA= `lambda=N=2700` t=5 min `N=N_(0)E^(-lambda tau)` `lambda=(2.303)/(5xx60) log_(10)(4700)/(2700)` `lambda=(0.693)/(T_(1/2))` `T_(1/2)=(0.693)/(0.00184)` `T_(1//2)=376.63 sec` `T_(1//2)=6.2 min` |
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