1.

The activity of a radionuclide (X^(100)) is 6.023 curie . If the disintegration constant is 3.7 xx 10^(4) sec^(-1) , the mass of the radionuclide is :

Answer»

`10^(-14) `g
`10^(-6)` g
`10^(-15)` g
`10^(-3)` g

Solution :`A = lambda . N , 6.023 xx 3.7 xx 10^(10) = 3.7 xx 10^(4) xx N_(t)`
`N_(t)=6.023 xx 10^(6) ` atom = `("wt")/(GAW) = (N_(t))/(6.023 xx 10^(23)) = 10^(-15)` GMS


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