The activity of the radioactive sample drops to(1/64)^(th)of its origi – InterviewSolution

1.	The activity of the radioactive sample drops to(1/64)^(th)of its original value in 2 hr find the decay constant (lambda).
Answer» Solution :`LAMBDA=(1)/(2) LN. (1)/((1//64))=2.079 HR^(-1)`

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