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The activity per ml of a solution of radioactive substances is x.How much water be added to 200 ml of this

Answer»


Solution :In solution,`x_A=0.3, x_B=0.7`
In VAPOUR PHASE, `x'_A=0.6,x'_B=0.4`
`x'_A=p_A/P=0.6`
`p_A/(p_A+p_B)=(p_A^@x_A)/(p_A^@x_A+p_B^@x_B)`
`0.6=(0.3p_A^@)/(0.3p_A^@+0.7p_B^@)`…(1)
`x'_B=p_B/P=p_B/(p_A+p_B)=0.4`
`IMPLIES (0.7p_B^@)/(0.3p_A^@+0.7p_B^@)=0.4`...(2)
DIVIDING (1) by (2)
`(0.3p_A^@)/(0.7p_B^@)=0.6/0.4`
`implies p_A^@/p_B^@=(0.6xx0.7)/(0.4xx0.3)=7/2=3.5`


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