1.

The acute angle between the lines y=3 and `y=sqrt(3x)+9` is:

Answer» Here, equation of Line 1 (`L_1`) is,
`y =3`
Equation of Line 2 (`L_2`) is ,
`y =sqrt3x+9`
The slope of `L_1,(m_1) = 0`
Slope of `L_2,(m_2) = sqrt3`
So, for acute angle `theta` between them,
`tan theta = (m_1+m_2)/(1-m_1m_2) = (0+sqrt3)/(1-0) = sqrt3`
`=>theta = pi/3`


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