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The acute angle between the lines y=3 and `y=sqrt(3x)+9` is: |
Answer» Here, equation of Line 1 (`L_1`) is, `y =3` Equation of Line 2 (`L_2`) is , `y =sqrt3x+9` The slope of `L_1,(m_1) = 0` Slope of `L_2,(m_2) = sqrt3` So, for acute angle `theta` between them, `tan theta = (m_1+m_2)/(1-m_1m_2) = (0+sqrt3)/(1-0) = sqrt3` `=>theta = pi/3` |
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