1.

The addition of HCl in propene proceeds via

Answer»

`CL^(+)` in first stpe
`H^(+)` in first step
`H^(-)` in first step
`Cl^(+) and H^(+)` in single step

Solution :Since oxygen is more ELECTRONEGATIVE than cl, therefore, heterolytic of HO-Cl gives `HO^(-) and Cl^(+)`. Since alkene UNDERGOES `E^(+) AR,` therefore the electrophilic `Cl^(+)` attack first to generate more stable carboncation, which then undergoes mcleophilic attackby `OH^(-)` to give propylene chlorohydrine
`CH_(3)-CH=CH_(2)+Cl^(+) to CH_(3)- overset(o+)(CH)-CH_(2)Cl`


Discussion

No Comment Found

Related InterviewSolutions