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The ages of 10 children residing in a colony are: 12, 15, 10, 13, 11, 14, 18, 17, 5, 18.Answer the following by matching the columns: Range of data Mean age Median age Modal age Number of children having age more than the mean age no spam |
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Answer» Answer: RANGE of data=10. MEAN age=€f(X)/€f=133/10=13.3. Median age=n+1/2=10+1/2=11/2=5.5=11 & 14. Modal age=18. Number of children having age more than the mean age=5. I THINK this is your answer. |
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