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The air resistance for a particular vehicle is proportional to square of its velocity. The ratio of power required at 40 km/hr to that reqd.at 80 km/hr is: |
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Answer» Solution :`F prop v^(2)implies F = KV^(2)`. Now `P=Pv=kv^(3)` `:. (P_(1))/(P_(2))=((v_(1))/(v_(2)))^(3)=(40/80)^(3)=1/8`. |
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