1.

The air resistance for a particular vehicle is proportional to square of its velocity. The ratio of power required at 40 km/hr to that reqd.at 80 km/hr is:

Answer»

<P>`1:1`
`1:2`
`1:4`
`1:8`

Solution :`F prop v^(2)implies F = KV^(2)`. Now `P=Pv=kv^(3)`
`:. (P_(1))/(P_(2))=((v_(1))/(v_(2)))^(3)=(40/80)^(3)=1/8`.


Discussion

No Comment Found

Related InterviewSolutions