The alkali metal cation having the least ionic mobility isA. `Li^(+)`B

1.	The alkali metal cation having the least ionic mobility isA. `Li^(+)`B. `Na^(+)`C. `K^(+)`D. `Cs^(+)`
Answer» Correct Answer - A The extent of hydration depends upon the size of the ion. Smaller the size of the ion, more highly it is hydrated and, hence, greater is its hydrated ionic radius, and less is its ionic mobility (condcutance). Thus, the order of ionic mobility is `Li^(+)ltNa^(+)ltK^(+)ltRb^(+)ltCs^(+)`

Discussion

No Comment Found

Related InterviewSolutions

In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam becauseA. Hg is more inert than PtB. more voltage is required to reduce `H^(+)` at Hg than at PtC. Na is dissolved in Hg while it does not dissove in PtD. concentration of `H^(+)` ions is larger when Pt electrode is taken
Which among the following is kinetically inert towards water?A. NaB. BeC. CaD. K
Which ions are produced when anhydrous KF is mixed with conc. HF?A. `K^(+),H^(+),F^(-)`B. `{KF^(+)(HF^(-))}`C. `KH^(+),F^(-)`D. `K^(+),HF_(2)^(-)`
Fill up the blanks with appropriate choice. Lithium and magnesium react slowly with water. their hydroxides are_____soluble in water. Carbonates of Li and Mg____easily on heating. Both LiCl and `MgCl_(2)` are_____in ethanol and are_______.they crystallise from their aqueous solutions as_____.A. More, do not decompose, soluble, hygroscopic, hydratesB. less, decompose, soluble, deliquescent, hydratesC. freely, sublime, insoluble, deliquescent, anhydrousD. freely, docompose, soluble, hygroscopic, crystals
The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` areA. 0 and -1B. `-1` and -2C. `-2` and 0D. `-2` and +1
An excess of `KO_(2)` is placed in a closed container of `CO_(2)`(g). After reaction is completed. Will the gas pressure be same, greater or less than initial value. Example.
Write balanced equations for reactions between a. `Na_(2)O_(2)` and water b. `KO_(2)` and water c. `Na_(2)O` and `CO_(2)`
Among `KO_(2),ALO_(2)^(Θ)`,`BaO_(2)` and `NO_(2)^(+)`,unpaired electrons is present in .A. `NO_(2)^(+) and BaO_(2)`B. `KO_(2) and AlO_(2)^(-)`C. `KO_(2)` onlyD. `BaO_(2)` only
The stability off `K_(2)O,K_(2)O_(2) and KO_(2)` is in order `K_(2)O lt K_(2)O_(2) lt KO_(2)`. This increasing stability as the size of metal ion increases is due to stabilisation ofA. larger cation by smaller anions through lattice energy effectsB. larger cation by larger anions through lattice energy effectsC. smaller cations by smaller anions through melting pointD. smaller cations by larger anions through melting point.
A metal `M` readily forms its sulphate `MSO_(4)` which is water soluble. It forms its oxide `MO` which becomes inert on heating. It forms its insoluble hydroxide `M(OH)_(2)` which is soluble in `NaOH` solution. Then `M` isA. `Be`B. BaC. CaD. Mg

The alkali metal cation having the least ionic mobility isA. `Li^(+)`B. `Na^(+)`C. `K^(+)`D. `Cs^(+)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment