1.

The alkyl halide that undergoes S_(N)I reaction more readily is :

Answer»

ethyl bromide
isopropyl bromide
vinyl bromine
t-butyl bromide

Solution :Since the reaction follows `S_(N)1` mechanism the alkyl halide giving most STABLE carbocation will be the most reactive.
`H_(3)C-underset("t-Butyl bromide")underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-BrrarrH_(3)C-underset(3^(@)" carbocation")underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C^(+))+Br^(-)`
Ethyl bromide and n-propyl bromide give primary carbocation, isopropyl bromide gives SECONDARY carbocation, t-butyl bromide gives `3^(@)` carbocation. ORDER of stability of carbocation is `3^(@)gt2^(@)gt1^(@)`. HENCE t-butyl bromide is the most stable.


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