The altitude and the base of a triangular field are in the ratio 6 : 5

1.	The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field. Area of the given triangular field =CostofthefieldRate=49,57,20036,720 hectare =135 hectare =135×10,000 sq. m=1350000 m2.
Answer» The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field. Area of the given triangular field $= \frac{C o s t o f t h e f i e l d}{R a t e} = \frac{49, 57, 200}{36, 720}$ hectare =135 hectare $= 135 \times 10, 000$ sq. m=1350000 $m^{2} .$

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field. Area of the given triangular field =CostofthefieldRate=49,57,20036,720 hectare =135 hectare =135×10,000 sq. m=1350000 m2.

Answer»

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field.

Area of the given triangular field $= \frac{C o s t o f t h e f i e l d}{R a t e} = \frac{49, 57, 200}{36, 720}$ hectare

=135 hectare

$= 135 \times 10, 000$ sq. m=1350000 $m^{2} .$

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