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The altitude of a triangle,whose area is 42cm² and base is 12cm,is ? |
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Answer» Lets take ALTITUDE as A,Area of the TRIANGLE = 42cm^2 1/2×B×A = 42cm^2 1/2×12×A = 42 6×A = 42 A = 42/6 A = 8cmTherefore, altitude is = 8CM |
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