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The ammonia molecule has a permanent electric dipole moment of 1.47 D where D is the debye unit and 1D=3.34 xx 10^(-30)Cm. Calculate the electric potential due to the ammonia molecule at a point distant 30 nm away along the dipole axis. |
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Answer» Solution :Data supplied, Dipole moment (p) `=1.47 xx 3.34 xx 10^(-30) C.m, r=30 xx 10^(-9) m =3 xx 10^(-8)m` Being ALONG the axis `theta=0, therefore cos theta=1` Potential `V=(1)/(4epsi_(0)). (p cos theta)/(r^(2))=(9 xx 10^(9) xx 1.47 xx 3.34 xx 10^(-30) xx 1)/(9 xx 10^(-16))=4.91 xx 10^(-5)V =49.1muV` |
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