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The amount of ""_(6)^(14)C isotope in a place of wood is found to be one fifth of that present in a fresh piece of wood. Calculate the age of the piece of wood (half-life of ""_(6)^(14)C=5577 year). |
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Answer» SOLUTION :`t=(2.303)/(lambda)LOG.(N_(0))/(N)` `impliest=(2.303xxt_(1//2))/(0.693)log.(N_(0))/(N)` `=(2.303xx5577)/(0.693)log.(N_(0))/(N_(0)//5)` `(2.303xx5577)/(0.693)xx0.6989=12.953` YEARS |
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