1.

The amount of anhydrous Na_(2)CO_(3) present in 250 ml of 0.25 M solution is

Answer»

6.225 G
66.25 g
6.0 g
6.625 g

SOLUTION :`M=(w)/(m xxV(L)) , 0.25 = (w)/(106xx0.25), w=6.625 GM`


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