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The amount of CO in a gas ample can be determined by using the reaction. `I_(2)O_(5)+5COtoI_(2)+5CO_(2)` If a gas sample liberated 0.2 g of `I_(2)`, how many g of CO were present in the sample. |
Answer» 1 mole of `CO=28 g.` 1 mole of `I_(2)=253.8g` 5 mole of `CO=1` mole of `I_(2)` Moles of `I_(2)=(0.2)/(253.8)` `therefore(0.2)/(253.8)` moles of `I_(2)=(5xx0.2)/(253.8)xx28g` of `CO` `=0.110 g` of `CO` |
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