1.

The amount of electrolytes required to coagulate a given amount of AgI colloidal solutio n (-ve charge) will be in the order

Answer»

`NaNO_(3) gt AL (NO_3)_3 gt Ba(NO_3)_2`
`Al(NO_3)_3 gt Ba(NO_3)_2 gt NaNO_3`
`Al (NO_3)_3 gt NaNO_(3) gt Ba(NO_3)_2`
`NaNO_(3)gt Ba(NO_3)_2 gt Al (NO_3)_3`

Solution :Accordin to HARDY Schulze law, for coagulation,
Quantity of electrolyte ` PROP (1)/("charge on the cation/anion")`
To coagulate AgI, `I^(-)` (-ve charge)is to be coagulated.
`Al (NO_3)_3 rarr 2 Al^(3+) +3NO_(3)^(-)`
`Ba(NO_3)_2 rarr Ba^(2) +2NO_(3)^(-)`
`NaNO_(3) rarr NA^(+) + NO_(3)^(-)`
Charge on the cation decreases in the order : `Al^(3+) gt Ba^(2+) gt Na^(-)`
Thus, the amountof electrolytes required will be in the order.
`NaNO_(3) gt Ba(NO_3)_2 gt Al (NO_3)_3`


Discussion

No Comment Found