1.

The amount of energy released when 20 mL of 0.5 M NH_4OH are mixed with 100 mL of 0.1 M HCl is x kJ. The heat of dissociation of NH_4OH will be (heat of neutralization of NaOH & HCl is y kJ/mol).

Answer»

`-100 x`
`y - 100 x`
`-100 x - y`
`100 x`

Solution :10 m mole `NH_4OH + 110 m "mole" HCl implies x kJ` heat is released
`:.` For 1 mole `implies 100 xx kJ` heat is released
`:. Delta H = -100 xx kJ//MOL`
For 1 mole `NAOH + 1"mole" HCl, Delta H = y kJ //mol "":. ""` Heat of DISSOCIATION of `NH_(4)OH = -100x - y`.


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