The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `200 cm^(3)` of `0.2 M NaOH` isA. `2.292 kJ`B. `1.292 kJ`C. `0.292 kJ`D. `5.292 kJ`

The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `

1.	The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `200 cm^(3)` of `0.2 M NaOH` isA. `2.292 kJ`B. `1.292 kJ`C. `0.292 kJ`D. `5.292 kJ`
Answer» Correct Answer - A `500cm^(3)` of `0.1 M HCl=0.05 mol`. `200 cm^(3)` of `0.2 MNaOH=0.04 mol` `0.04 mol` of `NaOH` neutralize `0.04 mol` of `HCl` and `0.04 mol` of `H_(2)O` is formed. Heat evolved `=57.3xx0.04=2.292 kJ`

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The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `200 cm^(3)` of `0.2 M NaOH` isA. `2.292 kJ`B. `1.292 kJ`C. `0.292 kJ`D. `5.292 kJ`

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