1.

The amount of heat evolved when 500cm^(3) of 0.1M HCl is mixed with 200cm^(3) of 0.2 M NaOH is

Answer»

2.292 kJ
1.292 kJ
0.292 kJ
3.392 kJ

Solution :Mili-equivalent of HCL = `500xx0.1`
=50 milli-moles = 0.05 moles
Milli-equivalent of NaOH= `200xx0.2`
= 40 milli-moles = 0.04 moles
When 1 MOLE of `H^(+)` ions and 1 mole of `OH^(-)` ions are neutralized, 1 mole of water is formed and 57.1 kJ of energy is released.
0.04 moles of `H^(+)` ions react with 0.04 moles of `OH^(-)` ions to form 0.04 moles of water molecules. Heat EVOLVED = `0.04xx57.1=2.29 kJ`.


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