1.

The amount of heat generated in 500 Omega resisttance, when the kye is thrown over from contanct 1 to 2, as shown in figure, is

Answer»

`6.25xx10^(-2)J`
`6.25xx10^(-3)J`
`3.75xx10^(-3)J`
`3.75xx10^(-2)J`

SOLUTION :`H_(500)=((500)/(300+500))1/2CV^(2)=5/8((1)/(2)CV^(2))`


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