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The amount of heat supplied to decrease the volume of an ice water mixture by `1 cm^(3)` without any change in temperature, is equal to: `(rho_("ice") = 0.9, rho_("water") = 80 cal//gm)`A. 360 calB. 500calC. 72 calD. 720 cal |
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Answer» Correct Answer - C `Q = m xx L_(ice) = rho_(ice)(V) L_(ice)`. |
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