1.

The amount of solute ( molar mass 60 g "mol"^(-1) ) that must be added to 180 g of water so that the vapour pressure of water is lowered by 10% is

Answer»

<P>30 g
60 g
120 g
12 g

Solution :`(p_(A)^(@)-p_(A))/(p_(A)^(@))=(w_(B)M_(A))/(w_(A)M_(B))`
`:.(10)/(100)=(w_(B)xx18)/(180xx60)`
`:.w_(B)=(10)/(100)xx(180xx60)/(18)=60G`


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