1.

The amount of solute required to prepare 10 L of a decimolar solution is :

Answer»

0.01 mol
0.2 mol
0.1 mol
1 mol

Solution :Molarity `=("Moles of solute")/("Volume")xx1000`
Moles of solute `=("Molarity" XX "Volume")/(1000)=(0.1xx10000)/(1000)=1`


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