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The amplifiers X, Y and Z are connected in series. If the voltage gains of X, Y and Zare 10, 20 and 30, respectively and the input signal is 1 mV peak value, then what is the output signal voltage (peak value) (i)if dc supply voltage is 10V? (ii) if dc supply voltage is 5V? |
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Answer» Solution :`A_(v)=(v_(0))/(v_(i))` `therefore (A_(v))_(1)xx (A_(v))_(2)xx(A_(v))_(3)=(v_(0))/(v_(i))` `therefore v_(0)=v_(i)xx(A_(v))_(1)xx(A_(v))_(2)xx(A_(v))_(3)` `therefore (v_(0))_("MAX")=(v_(i))_("max")xx(A_(v))_(1)xx(A_(v))_(2)xx (A_(v))_(3)` `therefore (v_(0))_("max")=(1xx10^(-3))(10)(20)(30)=6V` (i) When SUPPLY voltage is 10 V `therefore (v_(0))=6V (because 6V lt 10V)` (ii) When supply voltage is 5V `(v_(0))_("max")=5V (because 5V lt 6V)` |
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