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InterviewSolution
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The amplitude of a damped oscillator becomes half in one minutes. The amplitude after 3 minutes will be 1/x times of the original . Determine the value of x. |
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Answer» Amplitude of damped oscillations is `A=A_(0)e^(-gammat)` `" "`(from `x=x_(m)e^(-gammat)`) As `A=A_(0)//2 " at " t=1` minute, So `(A_(0))/(2)=A_(0)e^(-gamma) " or "e^(gamma)=2` After 3minutes the amplitude will be `A_(0)//x` So `(A_(0))/(x)=A_(0)e^(-gamma3)` or `x=e^(3y)=(e^(gamma))^(3)=2^(3)=8` |
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