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The amplitude of a particle executing SHM about `O` is `10 cm`. ThenA. when the `KE` is `0.64` times of its maximum`KE`, its displacement is `6cm` from `O`B. its speed is half the maximum speed when its displacement is half the maximum displacementC. Both (a) and (b) are correctD. Both (a) and (b) are wrong |
Answer» Correct Answer - A (a) Kinetic energy is `0.64` times, it means speed is `0.8` times `0.8 omega A = omega sqrt(A^(2)) - (x^(2))` `:. x = 0.6 A = 6cm` (b) `(omegaA) /(2) = omega sqrt(A^(2) - x^(2))` `:. x = sqrt(3)/(2) A` |
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