1.

The amplitude of S.H.M. atx=0.05 m is

Answer»

0.02 m
0.01 m
0.0141m
1.414 m

Solution :`R=2A COS (2PIX)/(0.4)==0.02cos((2pixx0.05)/(0.4))`
`=0.02cospi/4=0.02xx(1)/(SQRT2)=0.0141m`


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