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The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_(0)=510nT. What is the amplitude of the electric field part of the wave? |
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Answer» Solution :As `B_(0)=510nT=510xx10^(-9)T` `THEREFORE""E_(0)=B_(0).c=510xx10^(-9)xx3xx10^(8)=153NC^(-1)`. |
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