1.

The angle at which transmission intensity is max. Is

Answer»

`30^(@)`
`45^(@)`
`60^(@)`
`90^(@)`

Solution :`I_(3) = (I)/(8)SIN^(2)2theta_(1)`
For `I_(3)` to be max.
`sin^(2)2theta = 1`
then `theta_(1) = 45^(@)`.


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