The angle between the lines `2x=3y=-z and 6x=-y=-4z` is (A) `0^0` (B) `90^0` (C) `45^0` (D) `30^0`A. `0^(@)`B. `30^(@)`C. `45^(@)`D. `90^(@)`

The angle between the lines `2x=3y=-z and 6x=-y=-4z` is (A) `0^0` (B)

1.	The angle between the lines `2x=3y=-z and 6x=-y=-4z` is (A) `0^0` (B) `90^0` (C) `45^0` (D) `30^0`A. `0^(@)`B. `30^(@)`C. `45^(@)`D. `90^(@)`
Answer» Correct Answer - D The equations of the given lines can be written in the from `x/3=y/2=2/(-6)` and `x/1=y/(-6)=z/(-3//2)` Clearly `3xx1+2(-6)-6xx(-3/2)=0` So given lines are perpendicular to each other.

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The angle between the lines `2x=3y=-z and 6x=-y=-4z` is (A) `0^0` (B) `90^0` (C) `45^0` (D) `30^0`A. `0^(@)`B. `30^(@)`C. `45^(@)`D. `90^(@)`

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