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The angle of dip if dip needleoscillating invertical plane makes 40 oscillations per min in a magnetic meridian and 30 oscillations per minute in vertical plane at right angle to the magnetic meridian is |
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Answer» `theta=sin^(-1)(0.5625)` B=Total EARTH's field intensity v= vertical component of B `T'/T=sqrt(B)/(V)rArr(T)^(2)/(t6(2)=B/V` but`V=BsinthetarArr(T')/(T^(2))=(1)/(SINTHETA)rArrsintheta=(T^(@))/(T'^(2))` `T=60/40=(3)/(2)S` Also, and `T'=60/30=2s` `thereforesintheta=0.5625 rArr=sin^(-1)(0.5625)` |
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