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the angle of elevation from the top of a tower from the top of a ground which is 30m away from the foot of the tower is 30 degrees. what is the length of the tower |
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Answer» -step explanation:In ∆ ABC,tan 30° = AB/BC1/√3 = AB/3030/√3 = ABAB = 30/√3Now, MULTIPLYING numerator and denominator by 3 we get:AB = 30/√3 × √3/√3AB = 30√3/3AB = 10√3 THEREFORE, the height of the TOWER is 10√3. |
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