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the angle of elevation of the top of a tower at a point on the ground is 30°if on walking 20m toward the angle of elevation become 60°,then the height of the tower is |
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Answer» Given Let BC=x⟹AC=20+x From ΔBCD tan60=xCD CD=3X⋯(1)From ΔACD tan30=x+20CD CD=31(x+20)⋯(2)From (1)&(2) ⟹3x=31(x+20) ⟹3x=x+20 ⟹2x=20 ⟹x=10 From (1) HEIGHT of TOWER is 3x ⟹103 |
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