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The angle of incidence for a ray of light at a refracting surface of a prism is 45^@. The angle of prism is 60^@. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are |
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Answer» `30^@,sqrt2` `45^@+45^@=60^@+delta_m [because i=eimplies delta=delta_m]` `THEREFORE delta_m=30^@`  `mu=(sin((delta_m+A)/(2)))/(sin""A/2)` `=(sin((60^@+30^@)/(2)))/(sin((60^@)/(2)))` `=(sin45^@)/(sin 30^@)` `=(1)/(sqrt2)xx2/1` `=sqrt2` |
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