The angle of incidence of a wave of a wave with angle of transmission 45 degree and the refractive indices of the two media given by 2 and 1.3 is(a) 41.68(b) 61.86(c) 12.23(d) 27.89I had been asked this question during an online exam.Question is taken from Snell Law and Critical Angle in portion EM Wave Propagation of Electromagnetic Theory

The angle of incidence of a wave of a wave with angle of transmission

1.	The angle of incidence of a wave of a wave with angle of transmission 45 degree and the refractive indices of the two media given by 2 and 1.3 is(a) 41.68(b) 61.86(c) 12.23(d) 27.89I had been asked this question during an online exam.Question is taken from Snell Law and Critical Angle in portion EM Wave Propagation of Electromagnetic Theory
Answer» The correct answer is (a) 41.68 For EXPLANATION: The Snell law is GIVEN by N1 sin θi = N2 sin θt. To get θi, put N1 = 2, N2 = 1.3, θt = 45 DEGREE. THUS we get θi = sin^-1(1.3 sin 45)/2 = 41.68 degree.

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