1.

The angle of polarisation for any medium is 60^(@), what will be the critical angle for this?

Answer»

<P>`sin^(-1)((1)/(sqrt(3)))`
`tan^(-1) sqrt(3)`
`COS^(-)((1)/(sqrt(3)))`
`tan^(-1)((1)/(sqrt(3)))`

Solution :`u=tan theta_(p)=TAN60^(@)`
`:. MU=(1)/(sqrt(3))`
Critical angle,
`sin C=(1)/(mu)=(1)/(sqrt(3))`


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