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The angles of depression of the top and bottom of a building 50 meters high as observed from the top of a tower are 30 and 60 respectively. Find the height of the tower, and also the horizontal distance between the building and the tower. |
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Answer» ,TAN 30° = TP/BP 1/√3 = TP/BPBP = TP√3In ΔGTR,tan 60° = TR/GR√3 = TR/GRGR = TR/√3As BP = GRTP√3 = TR/√33 TP = TP + PR2 TP = BGTP = 50/2 m = 25 mNow, TR = TP + PRTR = (25 + 50) mHeight of tower = TR = 75 MDISTANCE between building and tower = GR = TR/√3GR = 75/√3 m = 25√3 m |
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