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InterviewSolution
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The angular speed of rotation of earth about its axis at which the weight of man standing on the equator becomes half of his weight at the poles is given byA. `0.034 rad s^(-1)`B. `8.75 xx 10^(-4) rad s^(-1)`C. `1.23 xx 10^(-2) rad s^(-1)`D. `7.65 xx 10^(-7) rad s^(-1)` |
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Answer» Correct Answer - B `g_("equator") = g - R omega^(2)` and `g_("pole") - R omega^(2)` `:. (g_("pole"))/(2)` or `(g)/(2) = g - R omega^(2)` or `omega sqrt((g)/(2R))` `= sqrt((9.8)/(2 xx 6.4 xx 10^(6))` `= 8.75 xx 10^(-4) rad//s` |
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