1.

The angular velocities of three bodies in simple harmonic motion are omega_(1),.omega_(2),omega_(3) with their respective amplitudes as A_(1),A_(2),A_(3). If all the three bodies have the same mass and velocity, then :

Answer»

`A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`
`A_(1)omega_(1)^(2)=A_(2)omega_(2)^(2)=A_(3)omega_(3)^(2)`
`A_(1)^(2)omega_(1)=A_(2)^(2)omega_(2)=A_(3)^(2)omega_(3)`
`A_(1)^(2)omega_(1)^(2)=A_(2)^(2)omega_(2)^(2)=A_(3)^(2)omega_(3)^(2)`.

Solution :Max VELOCITY `v=r OMEGA`
Since velocity is same
`:.""A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`
Correct choice is (a).


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