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The angular velocity and amplitude of simple pendulum are `omega` and r respectively. At a displacement x from the mean position, if its kinetic energy is T and potential energy is U, find the ration of T to U.A. `X^2omega^2//(a^2-X^2omega^2)`B. `X^2//(a^2-X^2)`C. `(a^2-X^2omega^2)//X^2omega^2`D. `(a^2-X^2)//X^2` |
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Answer» Correct Answer - B `T/V=(1/2momega^2(a^2-X^2))/(1/2momega^2X^2)=(a^2-X^2)/(X^2)` |
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