The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator isA. `sqrt((2GM)/(R^(3)))`B. `sqrt((2GM)/(R ))`C. `sqrt((2G^(2)M)/(R ))`D. `sqrt((2GM^(2))/(R ))`

The angular velocity of rotation of a planet of mass M and radius R, a

1.	The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator isA. `sqrt((2GM)/(R^(3)))`B. `sqrt((2GM)/(R ))`C. `sqrt((2G^(2)M)/(R ))`D. `sqrt((2GM^(2))/(R ))`
Answer» Correct Answer - A `V_(E )=sqrt((2GM)/(R ))` `therefore omega=(V_(E ))/(R )=(1)/(R )sqrt((2GM)/(R ))=sqrt((2GM)/(R^(3)))`

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The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator isA. `sqrt((2GM)/(R^(3)))`B. `sqrt((2GM)/(R ))`C. `sqrt((2G^(2)M)/(R ))`D. `sqrt((2GM^(2))/(R ))`

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