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The angular velocity of rotation of star (of mass M and radius R ) at which the matter start to escape from its equator will beA. `sqrt((2GR)/(M))`B. `sqrt((2GM)/(R^(3)))`C. `sqrt((2GM)/(R))`D. `sqrt(((2GM)^(2))/(R))` |
Answer» Correct Answer - b `v_(e)=sqrt((2GM)/(R))` `R_(omega)=sqrt((2GM)/(R)) " "therefore omega=sqrt((2GM)/(R^(3)))` |
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