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The answer to each of the following questions is a single-digit integer ranging from 0 to 9. Darken the correct digit. A uniform electric field exists in between the plates of a capacitor and potential difference between the plates is found to be V_(1). Now a dielectric slab of dielectric constant 2 is inserted in between the paltes. Thickness of the salb is half of the separationbetween the plates. The potential difference between the plates is V_(2) now. Calculate 3V_(1)//V_(2). |
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Answer» `V_(1)=Ed` Now when dielectric slab is introduced in between the plates then potential difference can be written as follows: `V_(2)=E(d-t)+(E//K)(t)` Here t is `d//2` and K = 2. On substituting we GET the following: `V_(2)=3V_(1)//4` hence `3V_(1)//V_(2)=4`. |
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