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The aperture of an electron microscope is 0.02, the accelerating potential is 10^(4) V Find the dimensions of details which may be resolved with the aid of this instrument.

Answer»


Solution :We USE the expression for the resolving power of a microscope (66.8), putting `sinu=0.02`. We can FIND the wavelength from the nonrelativistic formula, since the kinetic ENERGY of the electron of 10 keV is much LESS than its rest energy which is 510 keV.


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